3.8. Independent identically distributed random variables#

Definition 3.7 (Independent identically distributed (iid) random variables)

3.8.1. Law of the large numbers#

3.8.1.1. Weak form#

todo

3.8.1.2. Strong form#

todo

3.8.2. Central Limit Theorem#

Theorem 3.2 (CLT)

Let \(\{ X_k \}_{k=1:n}\) a sequence of iid random variables with average value \(\mathbb{E}[X_k] = \mu\) and finite1 variance \(\mathbb{E}[(X_k-\mu)^2] = \sigma^2 < \infty\), then the sample average

\[\overline{X}_n := \dfrac{1}{n} \sum_{k=1}^n X_k \ ,\]

converges in distribution - or weakly converges - to the normal distribution \(\mathscr{N}\left(\mu, \frac{\sigma^2}{n} \right)\),

\[\overline{X}_n \quad \rightarrow^d \quad \mathscr{N}\left(\mu, \frac{\sigma^2}{n} \right) \ .\]
Proof of CLT

Let \(\{ X_k \}_{k=1:n}\) the sequence of iid random variables. Thus, \(\sum_{k=1}^n X_k\) has expected value \(n \mu\) and variance \(n \sigma^2\). Let

\[Z_n := \dfrac{\sum_{k=1}^n X_k - n \mu}{\sqrt{n \sigma^2}} = \sum_{k=1}^{n} \dfrac{X_k - \mu}{\sqrt{n \sigma^2}} =: \sum_{k=1}^n \dfrac{Y_k}{\sqrt{n}} \ .\]

Expeceted value and variance of variables \(Y_k\) are respectively \(\mathbb{E}[Y_k] = 0\) and \(\mathbb{E}[Y_k^2] = 1\). The characteristic function of \(Z_n\), see Example 3.2 for the linear combination of independent variables, reads

\[\begin{split}\begin{aligned} \varphi_{Z_n}(t) & = \varphi_{Y_1} \left( \dfrac{t}{\sqrt{n}} \right) \dots \varphi_{Y_n} \left( \dfrac{t}{\sqrt{n}} \right) = && (1) \\ & = \left[ \varphi_{Y_1} \left( \dfrac{t}{\sqrt{n}} \right) \right]^n \ , \end{aligned}\end{split}\]

as \((1)\) the variables are not only independent but identically distributed: as they have the same pdf, they also have the same characteristic function. Expanding in Taylor series, see example Example 3.3 for \(\frac{t}{\sqrt{n}} \rightarrow 0\), the approximation of the characteristic function reads (remembering that \(Y_n\) have zero expected value and unit variance),

\[\varphi_{Y_1}\left( \dfrac{t}{\sqrt{n}} \right) \sim 1 - \dfrac{t^2}{2 n} \ ,\]

while

\[\varphi_{Z_n}(t) = \left[ \varphi_{Y_1} \left( \dfrac{t}{\sqrt{n}} \right) \right]^n \sim \left[ 1 - \dfrac{t^2}{2 n} \right]^n \sim e^{- \frac{t^2}{2}} \ ,\]

i.e. it converges to the characteristic function of a normal distribution \(\mathscr{N}(0,1)\), see Example 3.4.

Levy’s continuity theorem completes the proof. todo


1

Does the CLT hold for heavy-tailed distributions? See section about Rare Events. work-in-progress