3.8. Independent identically distributed random variables#
Definition 3.7 (Independent identically distributed (iid) random variables)
3.8.2. Central Limit Theorem#
Theorem 3.2 (CLT)
Let \(\{ X_k \}_{k=1:n}\) a sequence of iid random variables with average value \(\mathbb{E}[X_k] = \mu\) and finite1 variance \(\mathbb{E}[(X_k-\mu)^2] = \sigma^2 < \infty\), then the sample average
converges in distribution - or weakly converges - to the normal distribution \(\mathscr{N}\left(\mu, \frac{\sigma^2}{n} \right)\),
Proof of CLT
Let \(\{ X_k \}_{k=1:n}\) the sequence of iid random variables. Thus, \(\sum_{k=1}^n X_k\) has expected value \(n \mu\) and variance \(n \sigma^2\). Let
Expeceted value and variance of variables \(Y_k\) are respectively \(\mathbb{E}[Y_k] = 0\) and \(\mathbb{E}[Y_k^2] = 1\). The characteristic function of \(Z_n\), see Example 3.2 for the linear combination of independent variables, reads
as \((1)\) the variables are not only independent but identically distributed: as they have the same pdf, they also have the same characteristic function. Expanding in Taylor series, see example Example 3.3 for \(\frac{t}{\sqrt{n}} \rightarrow 0\), the approximation of the characteristic function reads (remembering that \(Y_n\) have zero expected value and unit variance),
while
i.e. it converges to the characteristic function of a normal distribution \(\mathscr{N}(0,1)\), see Example 3.4.
Levy’s continuity theorem completes the proof. todo
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Does the CLT hold for heavy-tailed distributions? See section about Rare Events. work-in-progress