9.1. Conduction#
Fourier model of heat condcution flux wants the heat flux to be proportional to the temperature gradient, \(\nabla T\). The most general expression for linear non-isotropic media reads
with \(\mathbb{K}\) the conductivity tensor (a second-oreder (semi)definite (symmetric? todo check, Onsager reciprocal relations) positive to comply with the second principle of thermodynamics: “heat transfers energy from hot to cold regions”). The behavior of isotorpic media is described by isotropic tensors; thus1 the conductivity tensor becomes \(\mathbb{K}^{iso} = k \mathbb{I}\), and the heat flux reads
Differential problem. It follows that conduction in a … medium in region \(\Omega\) for time \(t \in [t_0, t_1]\) is governed by the differential problem represented by the PDE
supplied with proper initial conditions in every point \(\vec{r} \in \Omega\)
and boundary conditions for every point on the boudary of the domain, \(\vec{r} \in \partial \Omega\) for every time \(t \in [t_0, t_1]\). Different boundary conditions may represent different physical processes:
known temperature on \(S_D\) (Dirichlet boundary conditions: the value of the unknown function is prescribed),
\[T(\vec{r}, t) = T_D (\vec{r}, t) \qquad \vec{r} \in S_D\]known heat flux on \(S_N\) (Neumann boundary conditions: the value of the directional derivative of the unknown function is prescribed, in the normal direction w.r.t. the boundary),
\[\hat{n}(\vec{r},t) \cdot \nabla T(\vec{r}, t) = \phi_N (\vec{r}, t) \qquad \vec{r} \in S_N\]known value of a linear combination of the value of the unknown function and its directional derivative (Robin boundary conditions),
\[\alpha T(\vec{r},t) + \beta \hat{n}(\vec{r},t) \cdot \nabla T(\vec{r}, t) = h(\vec{r},t) \qquad \vec{r} \in S_R\]
todo
derivation of this equation from governing equations of continuum mechanics: list assumptions, thermodynamic conditions (to transform internal energy \(e\) as a function of \(T\))
link to Mathematics:Numerical methods for PDEs:Elliptic (steady) and Parabolic (unsteady) problems
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Isotrpic 2-nd order tensors are the identity tensor and its multiples, \(\mathbb{A}^{iso} = a \mathbb{I}\). The dot product of 2-nd order identity tensor and a vector (field) gives the vector itself, \(\mathbb{I} \cdot \vec{v} = \vec{v}\).